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Beliebt Rechnen >

y^{''}+25y=0,y(0)=4.6,y^'(0)=-1.2

Lösung

y^{^{''}} + 25 y = 0, y (0) = 4.6, y^{^{'}} (0) = - 1.2

Lösung

y = 4.6 cos (5 t) - 0.24 sin (5 t)

Schritte zur Lösung

y^{''} (t) + 25 y = 0

Solve linear ODE:

y = 4.6 cos (5 t) - 0.24 sin (5 t)

y = 4.6 cos (5 t) - 0.24 sin (5 t)

Graph

Beliebte Beispiele

integral of x^5cos(x

\int x^{5} cos (d) x d x

(\partial)/(\partial x)(e^{2xy})

\frac{\partial}{\partial x} (e^{2 x y})

derivative of 4+8x-5x^2

\frac{d}{d x} (4 + 8 x - 5 x^{2})

integral of 8e^{4y}

\int 8 e^{4 y} d y

inverselaplace 1/((s^2+3))

in v erse l a pl a ce \frac{1}{( s ^{2} + 3 )}