(x-9)y^'+y=x^2-10

解答

(x - 9) y^{^{'}} + y = x^{2} - 10

y = \frac{x ^{3}}{3 ( x - 9 )} - \frac{10 x}{x - 9} + \frac{c _{1}}{x - 9}

求解步骤

(x - 9) y^{'} (x) + y = x^{2} - 10

求解线性方程:

y = \frac{x ^{3}}{3 ( x - 9 )} - \frac{10 x}{x - 9} + \frac{c _{1}}{x - 9}

y = \frac{x ^{3}}{3 ( x - 9 )} - \frac{10 x}{x - 9} + \frac{c _{1}}{x - 9}

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