integral from-18 to 32 of 1/(sqrt(|2x|))

解答

\int_{- 18}^{32} \frac{1}{∣ 2 x ∣} d x

14

求解步骤

\int_{- 18}^{32} \frac{1}{∣ 2 x ∣} d x

拿掉绝对值

= \int_{- 18}^{0} \frac{1}{- 2 x} d x + \int_{0}^{32} \frac{1}{2 x} d x

\int_{- 18}^{0} \frac{1}{- 2 x} d x = 6

\int_{0}^{32} \frac{1}{2 x} d x = 8

= 6 + 8

化简

= 14

in v erse l a pl a ce 3 - \frac{2}{s - 1}

a re a x^{2} - 6 x + 9, x^{2} - x + 6, [0, 5]

t \frac{d y}{d t} = t^{3} + 6 t^{3} y

x \to 0 + lim (x (12))

\int_{a}^{3 a} x d x