What is the integral from-1 to 1 of (x^4+3x+1) ?

The integral from-1 to 1 of (x^4+3x+1) is 12/5

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integral from-1 to 1 of (x^4+3x+1)

\int_{- 1}^{1} (x^{4} + 3 x + 1) d x

\frac{12}{5}

Decimal Notation

2.4

Solution steps

\int_{- 1}^{1} x^{4} + 3 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{4} d x + \int_{- 1}^{1} 3 x d x + \int_{- 1}^{1} 1 d x

\int_{- 1}^{1} x^{4} d x = \frac{2}{5}

\int_{- 1}^{1} 3 x d x = 0

\int_{- 1}^{1} 1 d x = 2

= \frac{2}{5} + 0 + 2

Simplify

\frac{2}{5} + 0 + 2 : \frac{12}{5}

= \frac{12}{5}

f (x) = e^{3 x^{2}}

\int - 7 x - 3 + \frac{2}{x - 1} d x

f (z) = \frac{z - 1}{z + 1}

\int 7 e^{2 x + e^{2 x}} d x

What is the integral from-1 to 1 of (x^4+3x+1) ?
The integral from-1 to 1 of (x^4+3x+1) is 12/5