What is the derivative of 6/(x+1) ?

The derivative of 6/(x+1) is -6/((x+1)^2)

What is the first derivative of 6/(x+1) ?

The first derivative of 6/(x+1) is -6/((x+1)^2)

\frac{d}{d x} (\frac{6}{x + 1})

- \frac{6}{( x + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{6}{x + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 6 \frac{d}{d x} (\frac{1}{x + 1})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 6 \frac{d}{d x} ((x + 1)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

= - \frac{1}{( x + 1 ) ^{2}} \frac{d}{d x} (x + 1)

\frac{d}{d x} (x + 1) = 1

= 6 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1)

Simplify

6 (- \frac{1}{( x + 1 ) ^{2}} \cdot 1) : - \frac{6}{( x + 1 ) ^{2}}

= - \frac{6}{( x + 1 ) ^{2}}

\frac{d}{d x} (cosh (x) - (2 e^{(- 0.3 x)}))

\frac{d}{d y} (e^{x} \cdot sin (y))

d er i v a t i v e 4 y

y^{^{''}} - 10 y^{^{'}} + 25 y = 0

n = 0 \sum \infty \frac{2 ^{n}}{n + 1}

What is the derivative of 6/(x+1) ?
The derivative of 6/(x+1) is -6/((x+1)^2)
What is the first derivative of 6/(x+1) ?
The first derivative of 6/(x+1) is -6/((x+1)^2)