What is (\partial)/(\partial y)(2x^4y-4) ?

The answer to (\partial)/(\partial y)(2x^4y-4) is 2x^4

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(\partial)/(\partial y)(2x^4y-4)

\frac{\partial}{\partial y} (2 x^{4} y - 4)

2 x^{4}

Solution steps

\frac{\partial}{\partial y} (2 x^{4} y - 4)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{4} y) - \frac{\partial}{\partial y} (4)

\frac{\partial}{\partial y} (2 x^{4} y) = 2 x^{4}

\frac{\partial}{\partial y} (4) = 0

= 2 x^{4} - 0

Simplify

= 2 x^{4}

\int sec (17 w) tan (17 w) d w

\frac{d}{d x} (ln (2 x - 1) + 2)

\frac{sin ( q ) + cos ( q )}{cos ( q )}

y^{^{''}} - 10 y^{^{'}} + 21 y = 0

\frac{4}{s ( s ^{2} + 2 s + 4 )}

What is (\partial)/(\partial y)(2x^4y-4) ?
The answer to (\partial)/(\partial y)(2x^4y-4) is 2x^4