limit as h approaches+0-of (2^h-1)/h

解答

h \to + 0 - lim (\frac{2 ^{h} - 1}{h})

ln (2)

十进制

0.69314 \dots

求解步骤

h \to 0 - lim (\frac{2 ^{h} - 1}{h})

使用洛必达法则

= h \to 0 - lim (\frac{ln ( 2 ) \cdot 2 ^{h}}{1})

代入值

h = 0

= \frac{ln ( 2 ) \cdot 2 ^{0}}{1}

化简

= ln (2)

\int \frac{1}{x ^{2} - 8 x + 25} d x

\frac{d}{d t} (2 sin (3 t))

s l o p e (80, 2000), (260, 5600)

\int_{2}^{7} \frac{1}{25 + ( x - 2 ) ^{2}} d x

\int (x^{\frac{3}{2}} - 5 x)^{2} d x