(x^2+y^2+x)dx+ydy=0

Lösung

(x^{2} + y^{2} + x) d x + y d y = 0

y = \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}, y = - \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}

Schritte zur Lösung

(x^{2} + y^{2} + x) d x + y d y = 0

Solve Bernoulli ODE:

y = \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}, y = - \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}

y = \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}, y = - \frac{- e ^{2 x} x ^{2} + c _{1}}{e ^{2 x}}

d er i v a t i v e f (x) = 9 x + 8

d er i v a t i v e \frac{2 x}{( x ^{3} - 6 ) ^{2}}

\frac{d}{d x} (\frac{sin ^{2} ( x )}{x})

d er i v a t i v e \frac{1}{3} x^{3} + 8 x^{2} + 63 x + 7

y^{^{''}} x + (\frac{2}{x} - \frac{2 x}{1 + x ^{2}}) \cdot y^{^{'}} = 0