(\partial)/(\partial t)(sin(2x)cos(2t))

解答

\frac{\partial}{\partial t} (sin (2 x) cos (2 t))

- 2 sin (2 x) sin (2 t)

求解步骤

\frac{\partial}{\partial t} (sin (2 x) cos (2 t))

将

x

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (2 x) \frac{\partial}{\partial t} (cos (2 t))

使用连锁律:

- sin (2 t) \frac{\partial}{\partial t} (2 t)

= - sin (2 t) \frac{\partial}{\partial t} (2 t)

\frac{\partial}{\partial t} (2 t) = 2

= sin (2 x) (- sin (2 t) \cdot 2)

化简

= - 2 sin (2 x) sin (2 t)

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