What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 ?

The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 is y=ln(2ln(x)+c_{1})x

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(2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 4

y = ln (2 ln (x) + c_{1}) x

Solution steps

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (2 ln (x) + c_{1}) x

y = ln (2 ln (x) + c_{1}) x

t an g e n t y = x^{2} - 5 x + 5

\int \frac{x ^{2}}{361 - x ^{2}} d x

\int \frac{4 x + 2}{x ^{2} + x + 5} d x

\frac{d ^{2} y}{d x ^{2}} - b y = 0

100 x - \frac{d y}{d x} = x y

What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 ?
The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=4 is y=ln(2ln(x)+c_{1})x