What is the derivative of 9cos(3x) ?

The derivative of 9cos(3x) is -27sin(3x)

What is the first derivative of 9cos(3x) ?

The first derivative of 9cos(3x) is -27sin(3x)

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\frac{d}{d x} (9 cos (3 x))

- 27 sin (3 x)

Solution steps

\frac{d}{d x} (9 cos (3 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (cos (3 x))

Apply the chain rule:

- sin (3 x) \frac{d}{d x} (3 x)

= - sin (3 x) \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= 9 (- sin (3 x) \cdot 3)

Simplify

= - 27 sin (3 x)

\frac{d}{d x} (4 a x)

x \to 2 - lim (∣ x ∣ - x^{2})

\frac{d}{d x} (\frac{5 x}{( x ^{2} - 1 )})

\int 8 x + 4 d x

\int 2 x \cdot e^{- 2 x} d x

What is the derivative of 9cos(3x) ?
The derivative of 9cos(3x) is -27sin(3x)
What is the first derivative of 9cos(3x) ?
The first derivative of 9cos(3x) is -27sin(3x)