What is the solution for y^'= x/y+(2y)/x ?

The solution for y^'= x/y+(2y)/x is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}

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y^'= x/y+(2y)/x

y^{^{'}} = \frac{x}{y} + \frac{2 y}{x}

y = x - 1 + c_{1} x^{2}, y = - x - 1 + c_{1} x^{2}

Solution steps

y^{'} (x) = \frac{x}{y} + \frac{2 y}{x}

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What is the solution for y^'= x/y+(2y)/x ?
The solution for y^'= x/y+(2y)/x is y=xsqrt(-1+c_{1)x^2},y=-xsqrt(-1+c_{1)x^2}