What is the limit as x approaches 0+of cos(x) ?

The limit as x approaches 0+of cos(x) is 1

limit as x approaches 0+of cos(x)

x \to 0 + lim (cos (x))

1

Solution steps

x \to 0 + lim (cos (x))

Plug in the value

x = 0

= cos (0)

Use the following trivial identity:

cos (0) = 1

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

= 1

y^{^{''}} + 0.2 x^{2} - 0.35 x = 0

n = 1 \sum \infty \frac{1}{2 ^{3 n}}

\frac{d}{d x} (y cos (x))

d er i v a t i v e cos (3 x^{2} + 4) \cdot 6 x

\int \frac{1}{3 x ^{2} + 6 x + 6} d x

What is the limit as x approaches 0+of cos(x) ?
The limit as x approaches 0+of cos(x) is 1