What is the derivative of 20x^3-6x^2+x ?

The derivative of 20x^3-6x^2+x is 60x^2-12x+1

What is the first derivative of 20x^3-6x^2+x ?

The first derivative of 20x^3-6x^2+x is 60x^2-12x+1

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\frac{d}{d x} (20 x^{3} - 6 x^{2} + x)

60 x^{2} - 12 x + 1

Solution steps

\frac{d}{d x} (20 x^{3} - 6 x^{2} + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (20 x^{3}) - \frac{d}{d x} (6 x^{2}) + \frac{d x}{d x}

\frac{d}{d x} (20 x^{3}) = 60 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d x}{d x} = 1

= 60 x^{2} - 12 x + 1

\frac{1}{s ^{2} - 4 s + 4}

\frac{d}{d x} (\frac{2}{x y})

\int_{0}^{\frac{π}{4}} 2 sec (x) d x

f^{^{'}} (x) = x^{2} e^{x^{2}}

\frac{3 x}{x + 1}

What is the derivative of 20x^3-6x^2+x ?
The derivative of 20x^3-6x^2+x is 60x^2-12x+1
What is the first derivative of 20x^3-6x^2+x ?
The first derivative of 20x^3-6x^2+x is 60x^2-12x+1