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Popular Calculus >

y^'=2y+e^x

Solution

y^{^{'}} = 2 y + e^{x}

Solution

y = - e^{x} + c_{1} e^{2 x}

Solution steps

y^{'} (x) = 2 y + e^{x}

Solve linear ODE:

y = - e^{x} + c_{1} e^{2 x}

y = - e^{x} + c_{1} e^{2 x}

Graph

Popular Examples

derivative of 4cos(cos(x))

d er i v a t i v e 4 cos (cos (x))

derivative of 3x^2cos(5x)

d er i v a t i v e 3 x^{2} cos (5 x)

derivative of f(x)=xcos(x)-sin(x)

d er i v a t i v e f (x) = x cos (x) - sin (x)

derivative of f(x)=ln(2x+1)

d er i v a t i v e f (x) = ln (2 x + 1)

integral from 0 to 4 of 1/(sqrt(64-x^2))

\int_{0}^{4} \frac{1}{64 - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=2y+e^x ?
The solution for y^'=2y+e^x is y=-e^x+c_{1}e^{2x}