derivative of 3^{x^2-x+5}

Lösung

\frac{d}{d x} (3^{x^{2} - x + 5})

ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)

Schritte zur Lösung

\frac{d}{d x} (3^{x^{2} - x + 5})

Wende Exponentenregel an:

a^{b} = e^{b l n (a)}

3^{x^{2} - x + 5} = e^{(x^{2} - x + 5) l n (3)}

= \frac{d}{d x} (e^{(x^{2} - x + 5) l n (3)})

Wende die Kettenregel an:

e^{(x^{2} - x + 5) l n (3)} \frac{d}{d x} ((x^{2} - x + 5) ln (3))

= e^{(x^{2} - x + 5) l n (3)} \frac{d}{d x} ((x^{2} - x + 5) ln (3))

\frac{d}{d x} ((x^{2} - x + 5) ln (3)) = ln (3) (2 x - 1)

= e^{(x^{2} - x + 5) l n (3)} ln (3) (2 x - 1)

e^{(x^{2} - x + 5) l n (3)} = 3^{x^{2} - x + 5}

= ln (3) \cdot 3^{x^{2} - x + 5} (2 x - 1)

\frac{d}{d x} (\frac{x ^{2} + 10 x}{( x + 5 ) ^{2}})

\frac{\partial}{\partial x} (4 u (x, y))

d er i v a t i v e \frac{1}{3 x ^{2}}

\frac{d}{d x} (\frac{1}{2} x^{2} 36 - x^{2})

n = 0 \sum \infty 2^{n} 1^{n}