derivative tan(e^{4t})+e^{tan(4t)}

Lösung

ableitung von

tan (e^{4 t}) + e^{t a n (4 t)}

sec^{2} (e^{4 t}) e^{4 t} \cdot 4 + e^{t a n (4 t)} sec^{2} (4 t) \cdot 4

Schritte zur Lösung

\frac{d}{d t} (tan (e^{4 t}) + e^{t a n (4 t)})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (tan (e^{4 t})) + \frac{d}{d t} (e^{t a n (4 t)})

\frac{d}{d t} (tan (e^{4 t})) = sec^{2} (e^{4 t}) e^{4 t} \cdot 4

\frac{d}{d t} (e^{t a n (4 t)}) = e^{t a n (4 t)} sec^{2} (4 t) \cdot 4

= sec^{2} (e^{4 t}) e^{4 t} \cdot 4 + e^{t a n (4 t)} sec^{2} (4 t) \cdot 4

y = (2 y^{4} + 2 x) y^{^{'}}

d er i v a t i v e \frac{e ^{2 x}}{sin ( 3 x )}

\int \frac{2 x}{3} d x

\int_{0}^{1} x 3 - x^{2} d x

t an g e n t f (x) = [1 + e^{x}] [ln (x)], at x = 1