integral of (6x+2)/(x^2+1)

Lösung

\int \frac{6 x + 2}{x ^{2} + 1} d x

3 ln x^{2} + 1 + 2 arctan (x) + C

Schritte zur Lösung

\int \frac{6 x + 2}{x ^{2} + 1} d x

Multipliziere aus

\frac{6 x + 2}{x ^{2} + 1} : \frac{6 x}{x ^{2} + 1} + \frac{2}{x ^{2} + 1}

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{6 x}{x ^{2} + 1} d x + \int \frac{2}{x ^{2} + 1} d x

\int \frac{6 x}{x ^{2} + 1} d x = 3 ln x^{2} + 1

\int \frac{2}{x ^{2} + 1} d x = 2 arctan (x)

= 3 ln x^{2} + 1 + 2 arctan (x)

Füge eine Konstante zur Lösung hinzu

= 3 ln x^{2} + 1 + 2 arctan (x) + C

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