integral from 1 to 9 of 6sqrt(u)

Lösung

\int_{1}^{9} 6 u d u

104

Schritte zur Lösung

\int_{1}^{9} 6 u d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{1}^{9} u d u

Wende die Potenzregel an

= 6 [\frac{2}{3} u^{\frac{3}{2}}]_{1}^{9}

Berechne die Grenzen:

\frac{52}{3}

= 6 \cdot \frac{52}{3}

Vereinfache

= 104

\int_{1}^{2} (x - 1)^{3} d x

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