What is the derivative of x^3-3x-5 ?

The derivative of x^3-3x-5 is 3x^2-3

What is the first derivative of x^3-3x-5 ?

The first derivative of x^3-3x-5 is 3x^2-3

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derivative of

x^{3} - 3 x - 5

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x - 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 3 x^{2} - 3 - 0

Simplify

= 3 x^{2} - 3

\frac{x ^{2}}{tan ( x )}

y = 4 cos (4 x^{2})

\frac{d}{d x} \frac{( x y )}{( x ^{2} + y ^{2} )}

\frac{1}{( 2 x + 1 )}

\frac{ln ( 1 )}{x}

What is the derivative of x^3-3x-5 ?
The derivative of x^3-3x-5 is 3x^2-3
What is the first derivative of x^3-3x-5 ?
The first derivative of x^3-3x-5 is 3x^2-3