What is the derivative of (x^3+3x^2)^4 ?

The derivative of (x^3+3x^2)^4 is 4(x^3+3x^2)^3(3x^2+6x)

What is the first derivative of (x^3+3x^2)^4 ?

The first derivative of (x^3+3x^2)^4 is 4(x^3+3x^2)^3(3x^2+6x)

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derivative of

(x^{3} + 3 x^{2})^{4}

4 (x^{3} + 3 x^{2})^{3} (3 x^{2} + 6 x)

Solution steps

\frac{d}{d x} ((x^{3} + 3 x^{2})^{4})

Apply the chain rule:

4 (x^{3} + 3 x^{2})^{3} \frac{d}{d x} (x^{3} + 3 x^{2})

= 4 (x^{3} + 3 x^{2})^{3} \frac{d}{d x} (x^{3} + 3 x^{2})

\frac{d}{d x} (x^{3} + 3 x^{2}) = 3 x^{2} + 6 x

= 4 (x^{3} + 3 x^{2})^{3} (3 x^{2} + 6 x)

\frac{( ( x ^{6} ) - 1 )}{( ( x ^{6} ) + 1 )}

\frac{( x ^{2} + 1 )}{x}

y = 3 cos (x) + 7 e x + ln (x^{2} + 1)

f (x) = \frac{4 x - 1}{x}

2^{z}

What is the derivative of (x^3+3x^2)^4 ?
The derivative of (x^3+3x^2)^4 is 4(x^3+3x^2)^3(3x^2+6x)
What is the first derivative of (x^3+3x^2)^4 ?
The first derivative of (x^3+3x^2)^4 is 4(x^3+3x^2)^3(3x^2+6x)