What is the derivative of ((1+e^x))/((1-e^x)) ?

The derivative of ((1+e^x))/((1-e^x)) is (2e^x)/((1-e^x)^2)

What is the first derivative of ((1+e^x))/((1-e^x)) ?

The first derivative of ((1+e^x))/((1-e^x)) is (2e^x)/((1-e^x)^2)

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derivative of

\frac{( 1 + e ^{x} )}{( 1 - e ^{x} )}

\frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 + e ^{x}}{1 - e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 1 + e ^{x} ) ( 1 - e ^{x} ) - \frac{d}{d x} ( 1 - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}}

\frac{d}{d x} (1 + e^{x}) = e^{x}

\frac{d}{d x} (1 - e^{x}) = - e^{x}

= \frac{e ^{x} ( 1 - e ^{x} ) - ( - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}}

Simplify

\frac{e ^{x} ( 1 - e ^{x} ) - ( - e ^{x} ) ( 1 + e ^{x} )}{( 1 - e ^{x} ) ^{2}} : \frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

= \frac{2 e ^{x}}{( 1 - e ^{x} ) ^{2}}

d er i v a t i v e 5 x^{6}

d er i v a t i v e 2 e^{3} t sin (2 t)

d er i v a t i v e tan (e^{s}) in x^{2}

d er i v a t i v e (1 + x)^{2 y + 1}

d er i v a t i v e y = (sin (x))^{5}

What is the derivative of ((1+e^x))/((1-e^x)) ?
The derivative of ((1+e^x))/((1-e^x)) is (2e^x)/((1-e^x)^2)
What is the first derivative of ((1+e^x))/((1-e^x)) ?
The first derivative of ((1+e^x))/((1-e^x)) is (2e^x)/((1-e^x)^2)