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Beliebt Rechnen >

integral of (x^2)/(1+sqrt(x))

Lösung

\int \frac{x ^{2}}{1 + x} d x

Lösung

\frac{2}{5} x^{\frac{5}{2}} - \frac{x ^{2}}{2} + \frac{2}{3} x^{\frac{3}{2}} - x + 2 x - 2 ln x + 1 + C

Schritte zur Lösung

\int \frac{x ^{2}}{1 + x} d x

Wende U-Substitution an

= \int \frac{2 u ^{5}}{1 + u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{u ^{5}}{1 + u} d u

Lange Division

\frac{u ^{5}}{1 + u} : u^{4} - u^{3} + u^{2} - u + 1 - \frac{1}{u + 1}

= 2 \cdot \int u^{4} - u^{3} + u^{2} - u + 1 - \frac{1}{u + 1} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{4} d u - \int u^{3} d u + \int u^{2} d u - \int u d u + \int 1 d u - \int \frac{1}{u + 1} d u)

\int u^{4} d u = \frac{u ^{5}}{5}

\int u^{3} d u = \frac{u ^{4}}{4}

\int u^{2} d u = \frac{u ^{3}}{3}

\int u d u = \frac{u ^{2}}{2}

\int 1 d u = u

\int \frac{1}{u + 1} d u = ln ∣ u + 1 ∣

= 2 (\frac{u ^{5}}{5} - \frac{u ^{4}}{4} + \frac{u ^{3}}{3} - \frac{u ^{2}}{2} + u - ln ∣ u + 1 ∣)

Setze in

u = x

ein

= 2 (\frac{( x ) ^{5}}{5} - \frac{( x ) ^{4}}{4} + \frac{( x ) ^{3}}{3} - \frac{( x ) ^{2}}{2} + x - ln x + 1)

Vereinfache

2 (\frac{( x ) ^{5}}{5} - \frac{( x ) ^{4}}{4} + \frac{( x ) ^{3}}{3} - \frac{( x ) ^{2}}{2} + x - ln x + 1) : \frac{2}{5} x^{\frac{5}{2}} - \frac{x ^{2}}{2} + \frac{2}{3} x^{\frac{3}{2}} - x + 2 x - 2 ln x + 1

= \frac{2}{5} x^{\frac{5}{2}} - \frac{x ^{2}}{2} + \frac{2}{3} x^{\frac{3}{2}} - x + 2 x - 2 ln x + 1

Füge eine Konstante zur Lösung hinzu

= \frac{2}{5} x^{\frac{5}{2}} - \frac{x ^{2}}{2} + \frac{2}{3} x^{\frac{3}{2}} - x + 2 x - 2 ln x + 1 + C

Graph

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