integral of (x^2+3x-5)ln(x)

Lösung

\int (x^{2} + 3 x - 5) ln (x) d x

\frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9} + 3 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) - 5 (x ln (x) - x) + C

Schritte zur Lösung

\int (x^{2} + 3 x - 5) ln (x) d x

Multipliziere aus

(x^{2} + 3 x - 5) ln (x) : x^{2} ln (x) + 3 x ln (x) - 5 ln (x)

= \int x^{2} ln (x) + 3 x ln (x) - 5 ln (x) d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} ln (x) d x + \int 3 x ln (x) d x - \int 5 ln (x) d x

\int x^{2} ln (x) d x = \frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9}

\int 3 x ln (x) d x = 3 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4})

\int 5 ln (x) d x = 5 (x ln (x) - x)

= \frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9} + 3 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) - 5 (x ln (x) - x)

Füge eine Konstante zur Lösung hinzu

= \frac{1}{3} x^{3} ln (x) - \frac{x ^{3}}{9} + 3 (\frac{1}{2} x^{2} ln (x) - \frac{x ^{2}}{4}) - 5 (x ln (x) - x) + C

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