integral from-3 to-2 of (y+2)/(y^2+4y)

Lösung

\int_{- 3}^{- 2} \frac{y + 2}{y ^{2} + 4 y} d y

- \frac{1}{2} ln (3) + ln (2)

Dezimale

0.14384 \dots

Schritte zur Lösung

\int_{- 3}^{- 2} \frac{y + 2}{y ^{2} + 4 y} d y

Wende U-Substitution an

= \int_{- 3}^{- 4} \frac{1}{2 u} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{- 4}^{- 3} \frac{1}{2 u} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int_{- 4}^{- 3} \frac{1}{u} d u

Nutze das gemeinsame Integral :

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{2} [ln ∣ u ∣]_{- 4}^{- 3}

Berechne die Grenzen:

ln (3) - 2 ln (2)

= - \frac{1}{2} (ln (3) - 2 ln (2))

Vereinfache

= - \frac{1}{2} ln (3) + ln (2)

\int_{- 3}^{1} \frac{1}{( 2 x + 6 ) ^{\frac{2}{3}}} d x

\int_{- \infty}^{0} 2 e^{- 3 x} d x

\int_{- 6}^{- 2} (- x + 1) d x

\int_{0}^{π} sin (x) e^{- s x} d x

\int_{0}^{t} e^{- (t - x)} d x