(1+y)dy-xdx=0

Lösung

(1 + y) d y - x d x = 0

y = - 1 + x^{2} + c_{1} + 1, y = - x^{2} + c_{1} + 1 - 1

Schritte zur Lösung

(1 + y) d y - x d x = 0

Solve separable ODE:

y = - 1 + x^{2} + c_{1} + 1, y = - x^{2} + c_{1} + 1 - 1

y = - 1 + x^{2} + c_{1} + 1, y = - x^{2} + c_{1} + 1 - 1

y^{^{'}} = \frac{x + 2}{y ^{2}}

y^{^{'}} = (y + 2)^{2}

\frac{d y}{d x} = 12 x y - 2 x

y^{^{'}} = (\frac{x}{y}) (\frac{y ^{2} + 1}{x ^{2} - 1})

\frac{d y}{d x} + 9 x e^{y} = 0