y^'=2(1+x)(1+y^2)

Lösung

y^{^{'}} = 2 (1 + x) (1 + y^{2})

y = tan (x^{2} + 2 x + c_{1})

Schritte zur Lösung

y^{'} (x) = 2 (1 + x) (1 + y^{2})

Solve separable ODE:

y = tan (x^{2} + 2 x + c_{1})

y = tan (x^{2} + 2 x + c_{1})

\frac{d y}{d x} e^{x + y} - x = 0

x y^{^{'}} = 3 (y^{2} + y)

y^{^{'}} = x y, y (1) = 1

\frac{d v}{d t} + \frac{v}{3} = 4

\frac{5}{3} y + \frac{d y}{d x} = 3 - 5 y