y^{''}+16y=0,y(0)=0,y^'(0)=1

Lösung

y^{^{''}} + 16 y = 0, y (0) = 0, y^{^{'}} (0) = 1

y = \frac{1}{4} sin (4 t)

Schritte zur Lösung

y^{''} (t) + 16 y = 0

Solve linear ODE:

y = \frac{1}{4} sin (4 t)

y = \frac{1}{4} sin (4 t)

y^{^{''}} + y^{^{'}} - 56 y = 0, y (0) = 5, y^{^{'}} (0) = 5

y^{^{''}} + c y^{^{'}} = 0

9 y^{^{''}} - 12 y^{^{'}} + 4 y = 0, y (0) = 2, y^{^{'}} (0) = 3

y^{^{''}} - 8 y^{^{'}} - 33 y = 0, y (0) = 0, y^{^{'}} (0) = - 7

l in e a r y^{^{''}} + y = 0