2y^{''}+18y=6tan(3t)

Lösung

2 y^{^{''}} + 18 y = 6 tan (3 t)

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{2 cos ( 3 t ) ( - ln ( tan ( 3 t ) + sec ( 3 t ) ) + sin ( 3 t ) ) - sin ( 6 t )}{6}

Schritte zur Lösung

2 y^{''} (t) + 18 y = 6 tan (3 t)

Solve linear ODE:

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{2 cos ( 3 t ) ( - ln ( tan ( 3 t ) + sec ( 3 t ) ) + sin ( 3 t ) ) - sin ( 6 t )}{6}

y = c_{1} cos (3 t) + c_{2} sin (3 t) + \frac{2 cos ( 3 t ) ( - ln ( tan ( 3 t ) + sec ( 3 t ) ) + sin ( 3 t ) ) - sin ( 6 t )}{6}

\int_{0}^{1} 2 π (x) (7 - 6 x - x^{2}) d x

\int \frac{1}{1 - 4 x ^{2}} d x

\int \frac{1}{121 - x ^{2}} d x

d er i v a t i v e sin (x) + \frac{1}{2} cot (x)

d er i v a t i v e y = \frac{ln ( x )}{1 + ln ( x )}