y^'=(x^2+3x+2)/(y-2)

Lösung

y^{^{'}} = \frac{x ^{2} + 3 x + 2}{y - 2}

y = \frac{12 + 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}, y = \frac{12 - 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}

Schritte zur Lösung

y^{'} (x) = \frac{x ^{2} + 3 x + 2}{y - 2}

Solve separable ODE:

y = \frac{12 + 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}, y = \frac{12 - 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}

y = \frac{12 + 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}, y = \frac{12 - 144 - 12 ( - c _{1} - 12 x - 9 x ^{2} - 2 x ^{3} )}{6}

\frac{d}{d x} (arctan^{2} (x^{3}))

\frac{\partial}{\partial y} (e^{y} \cdot sin (x))

t an g e n t f (x) = \frac{1}{2 x + !}

l a pl a ce t r an s f or m - 4 t^{2} δ (t - 2)

a re a 4 x^{2}, x^{2} + 3