(y^')/(x^3+y)= 1/x

Lösung

\frac{y ^{^{'}}}{x ^{3} + y} = \frac{1}{x}

y = \frac{x ^{3}}{2} + c_{1} x

Schritte zur Lösung

\frac{y ^{'} ( x )}{x ^{3} + y} = \frac{1}{x}

Solve linear ODE:

y = \frac{x ^{3}}{2} + c_{1} x

y = \frac{x ^{3}}{2} + c_{1} x

\int \frac{co tan ( ln ( x ) )}{2 x}

\frac{\partial ^{2}}{\partial y ^{2}} (x^{3} + 3 x y^{2})

x \to 0 - lim (\frac{2}{e ^{x} + 1})

t an g e n t x \frac{1}{x ^{3}}

\frac{d y}{d x} + 3 y = e^{- 3 x}