limit as x approaches infinity of-1/3 ce^{-3(x)}

解答

x \to \infty lim (- \frac{1}{3} c e^{- 3 (x)})

0

求解步骤

x \to \infty lim (- \frac{1}{3} c e^{- 3 x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= - \frac{1}{3} c \cdot x \to \infty lim (e^{- 3 x})

化简

- \frac{1}{3} c : - \frac{c}{3}

= - \frac{c}{3} \cdot x \to \infty lim (e^{- 3 x})

使用极限链式法则:

0

= - \frac{c}{3} \cdot 0

化简

= 0

\int (\frac{2}{x} - 4 e^{x}) d x

\frac{d}{d x} ((\frac{1}{x ^{2}}) d x)

a re a 4 x, x^{2}

\frac{d y}{d x} + y^{5} x + 5 y = 0

d er i v a t i v e y = \frac{5 x ^{3}}{3} - x + 7 e^{x}