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人気のある微分積分 >

(\partial)/(\partial x)(2x+1)

解

\frac{\partial}{\partial x} (2 x + 1)

解

2

解答ステップ

\frac{\partial}{\partial x} (2 x + 1)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x) + \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (2 x) = 2

\frac{\partial}{\partial x} (1) = 0

= 2 + 0

簡素化

= 2

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