-6y^{''}+24y=0

Lösung

- 6 y^{^{''}} + 24 y = 0

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

Schritte zur Lösung

- 6 y^{''} (t) + 24 y = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t}

\frac{\partial}{\partial y} (x y e^{x z})

x \to - \infty lim (x^{2} + 2 x)

\frac{d}{d x} (- \frac{15 x ^{4}}{2} + \frac{6 x ^{2}}{5} - \frac{x}{3} - 4)

\int x cos^{3} (x) d x

x \to 0 lim (\frac{ln ( 1 + \frac{1}{x} )}{x})