d/(dt)(sqrt(6/5-t^2))

Lösung

\frac{d}{d t} (\frac{6}{5} - t^{2})

- \frac{5 t}{6 - 5 t ^{2}}

Schritte zur Lösung

\frac{d}{d t} (\frac{6}{5} - t^{2})

Wende die Kettenregel an:

\frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

= \frac{1}{2 \frac{6}{5} - t ^{2}} \frac{d}{d t} (\frac{6}{5} - t^{2})

\frac{d}{d t} (\frac{6}{5} - t^{2}) = - 2 t

= \frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t)

Vereinfache

\frac{1}{2 \frac{6}{5} - t ^{2}} (- 2 t) : - \frac{5 t}{6 - 5 t ^{2}}

= - \frac{5 t}{6 - 5 t ^{2}}

a re a \frac{x ^{2}}{8}, 2 x^{2}, 2, 0

n = 1 \sum \infty n! x^{n}

\frac{d}{d y} (x y 1 - \frac{x ^{2}}{4} - \frac{y ^{2}}{9})

x \to 0 lim (\frac{x ^{2} - 3 x}{2 x})

\int_{- \infty}^{0} 15 x e^{3 x} d x