y^{''}-ay^'=0

Lösung

y^{^{''}} - a y^{^{'}} = 0

y = c_{1} e^{a t} + c_{2}

Schritte zur Lösung

y^{''} (t) - a y^{'} (t) = 0

Solve linear ODE:

y = c_{1} e^{a t} + c_{2}

y = c_{1} e^{a t} + c_{2}

t an g e n t 5 = (x + 9)^{2} + (y - 2)^{2}, (- 7, 3)

e^{2 x} \frac{d y}{d x} - e^{x} y = e^{- x} y^{2}

\frac{d}{d x} (\frac{- x}{1 + x ^{2}})

a re a y = x^{3} - x^{2}, y = 0

\frac{\partial}{\partial x} (3 x^{2} y^{4} + 1)