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人気のある微分積分 >

xy^'+2y^'-(x+2)sin(x)+y=0

解

x y^{^{'}} + 2 y^{^{'}} - (x + 2) sin (x) + y = 0

解

y = - cos (x) + \frac{sin ( x )}{x + 2} + \frac{c _{1}}{x + 2}

解答ステップ

x y^{'} (x) + 2 y^{'} (x) - (x + 2) sin (x) + y = 0

線形 ODE を解く:

y = - cos (x) + \frac{sin ( x )}{x + 2} + \frac{c _{1}}{x + 2}

y = - cos (x) + \frac{sin ( x )}{x + 2} + \frac{c _{1}}{x + 2}

グラフ

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