derivative of 8x^4-24x^2+r-1

Lösung

\frac{d}{d x} (8 x^{4} - 24 x^{2} + r (x) - 1)

32 x^{3} - 48 x + \frac{d r}{d x}

Schritte zur Lösung

\frac{d}{d x} (8 x^{4} - 24 x^{2} + r - 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x^{4}) - \frac{d}{d x} (24 x^{2}) + \frac{d r}{d x} - \frac{d}{d x} (1)

\frac{d}{d x} (8 x^{4}) = 32 x^{3}

\frac{d}{d x} (24 x^{2}) = 48 x

\frac{d}{d x} (1) = 0

= 32 x^{3} - 48 x + \frac{d r}{d x} - 0

Vereinfache

= 32 x^{3} - 48 x + \frac{d r}{d x}

e x t re m e x^{3} - 3 x^{2} - 23 x + 8

e x t re m e 6 x^{5} + 33 x^{4} - 30 x^{3} + 100

e x t re m e f (x, y) = x^{2} + y^{2} - 10

e x t re m e f (x) = \frac{( x + 1 )}{x ^{2} + x + 1}

e x t re m e f (x) = x, 0 \leq x \leq 16