What is the extreme f(x)=12x^2-2x^3 ?

The extreme f(x)=12x^2-2x^3 is Minimum(0,0),Maximum(4,64)

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extreme f(x)=12x^2-2x^3

extreme points

f (x) = 12 x^{2} - 2 x^{3}

Minimum (0, 0), Maximum (4, 64)

Solution steps

f^{'} (x) = 24 x - 6 x^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 0

into

12 x^{2} - 2 x^{3} : 0

Minimum (0, 0)

Plug

x = 4

into

12 x^{2} - 2 x^{3} : 64

Maximum (4, 64)

Minimum (0, 0), Maximum (4, 64)

f (x, y) = x^{2} + y^{2} - 4 y + 4

f (x) = x^{3} - 29 x^{2} - 40 x

f (x) = - 4 x^{2} - 8 x - 1.5

f (x, y) = 3 x - 4 x y + 5 y

f (x) = x^{5} + 243

What is the extreme f(x)=12x^2-2x^3 ?
The extreme f(x)=12x^2-2x^3 is Minimum(0,0),Maximum(4,64)