What is the extreme f(x)=2x^2-100ln(x) ?

The extreme f(x)=2x^2-100ln(x) is Minimum(5,50-100ln(5))

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extreme f(x)=2x^2-100ln(x)

extreme points

f (x) = 2 x^{2} - 100 ln (x)

Minimum (5, 50 - 100 ln (5))

Solution steps

f^{'} (x) = 4 x - \frac{100}{x}

Find intervals:

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

2 x^{2} - 100 ln (x) : 50 - 100 ln (5)

Minimum (5, 50 - 100 ln (5))

x^{3} - 4 x

\frac{x}{x ^{2} + 16 x + 60}

∣ sin (x) ∣

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 4

x^{3} + 2 x^{2} + x + 2

What is the extreme f(x)=2x^2-100ln(x) ?
The extreme f(x)=2x^2-100ln(x) is Minimum(5,50-100ln(5))