16x^2+25y^2+160x+200y+400=0

Lösung

16 x^{2} + 25 y^{2} + 160 x + 200 y + 400 = 0

(h, k) = (- 5, - 4), a = 5, b = 4

Schritte zur Lösung

16 x^{2} + 25 y^{2} + 160 x + 200 y + 400 = 0

Rewrite

16 x^{2} + 25 y^{2} + 160 x + 200 y + 400 = 0

in the form of the standard ellipse equation

\frac{( x - ( - 5 ) ) ^{2}}{5 ^{2}} + \frac{( y - ( - 4 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 5, - 4), a = 5, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (- 5, - 4), a = 5, b = 4

36 x^{2} + 5 y^{2} + 216 x - 60 y + 324 = 0

x^{2} + 4 y^{2} + 8 x + 9 y - 9 = 0

17 x^{2} + 1 0^{2} x + 10 y^{2} + 80 y + 143 = 0

169 x^{2} + 144 y^{2} - 338 x - 864 y - 22871 = 0

x^{2} + y^{2} < 2 y