sin^4(x)+cos^4(x)= 7/9

Solución

sin^{4} (x) + cos^{4} (x) = \frac{7}{9}

x = 0.36486 \dots + 2 πn, x = 2 π - 0.36486 \dots + 2 πn, x = 2.77672 \dots + 2 πn, x = - 2.77672 \dots + 2 πn, x = 1.20593 \dots + 2 πn, x = 2 π - 1.20593 \dots + 2 πn, x = 1.93566 \dots + 2 πn, x = - 1.93566 \dots + 2 πn

Pasos de solución

sin^{4} (x) + cos^{4} (x) = \frac{7}{9}

Restar

\frac{7}{9}

de ambos lados

sin^{4} (x) + cos^{4} (x) - \frac{7}{9} = 0

Simplificar

sin^{4} (x) + cos^{4} (x) - \frac{7}{9} : \frac{9 sin ^{4} ( x ) + 9 cos ^{4} ( x ) - 7}{9}

\frac{9 sin ^{4} ( x ) + 9 cos ^{4} ( x ) - 7}{9} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

9 sin^{4} (x) + 9 cos^{4} (x) - 7 = 0

Aplicar regla de los exponentes:

a^{b} = a^{2} a^{b - 2}

- 7 + 9 cos^{4} (x) + 9 sin^{2} (x) sin^{2} (x) = 0

Re-escribir usando identidades trigonométricas

2 - 18 cos^{2} (x) + 18 cos^{4} (x) = 0

Usando el método de sustitución

cos (x) = \frac{3 + 5}{6}, cos (x) = - \frac{3 + 5}{6}, cos (x) = \frac{3 - 5}{6}, cos (x) = - \frac{3 - 5}{6}

cos (x) = \frac{3 + 5}{6} : x = arccos \frac{3 + 5}{6} + 2 πn, x = 2 π - arccos \frac{3 + 5}{6} + 2 πn

cos (x) = - \frac{3 + 5}{6} : x = arccos - \frac{3 + 5}{6} + 2 πn, x = - arccos - \frac{3 + 5}{6} + 2 πn

cos (x) = \frac{3 - 5}{6} : x = arccos \frac{3 - 5}{6} + 2 πn, x = 2 π - arccos \frac{3 - 5}{6} + 2 πn

cos (x) = - \frac{3 - 5}{6} : x = arccos - \frac{3 - 5}{6} + 2 πn, x = - arccos - \frac{3 - 5}{6} + 2 πn

Combinar toda las soluciones

x = arccos \frac{3 + 5}{6} + 2 πn, x = 2 π - arccos \frac{3 + 5}{6} + 2 πn, x = arccos - \frac{3 + 5}{6} + 2 πn, x = - arccos - \frac{3 + 5}{6} + 2 πn, x = arccos \frac{3 - 5}{6} + 2 πn, x = 2 π - arccos \frac{3 - 5}{6} + 2 πn, x = arccos - \frac{3 - 5}{6} + 2 πn, x = - arccos - \frac{3 - 5}{6} + 2 πn

Mostrar soluciones en forma decimal

x = 0.36486 \dots + 2 πn, x = 2 π - 0.36486 \dots + 2 πn, x = 2.77672 \dots + 2 πn, x = - 2.77672 \dots + 2 πn, x = 1.20593 \dots + 2 πn, x = 2 π - 1.20593 \dots + 2 πn, x = 1.93566 \dots + 2 πn, x = - 1.93566 \dots + 2 πn

tan (\frac{θ}{5}) + 3 = 0

3 tan (x) - 3 = 0, 0 \leq x < 2 π

sec^{2} (θ) = 2

sin^{2} (θ) = 8 - 2 cos^{2} (θ)

10 sin (x) + 16 = 3 sin (x) + 9