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受欢迎的三角函数 >

4cos^2(β)-4cos(β)=3

解答

4 cos^{2} (β) - 4 cos (β) = 3

解答

β = \frac{2 π}{3} + 2 πn, β = \frac{4 π}{3} + 2 πn

+1

度数

β = 12 0^{\circ} + 36 0^{\circ} n, β = 24 0^{\circ} + 36 0^{\circ} n

求解步骤

4 cos^{2} (β) - 4 cos (β) = 3

用替代法求解

4 cos^{2} (β) - 4 cos (β) = 3

令

: cos (β) = u

4 u^{2} - 4 u = 3

4 u^{2} - 4 u = 3 : u = \frac{3}{2}, u = - \frac{1}{2}

4 u^{2} - 4 u = 3

将

3

para o lado esquerdo

4 u^{2} - 4 u = 3

两边减去

3

4 u^{2} - 4 u - 3 = 3 - 3

化简

4 u^{2} - 4 u - 3 = 0

4 u^{2} - 4 u - 3 = 0

使用求根公式求解

4 u^{2} - 4 u - 3 = 0

二次方程求根公式:

若

a = 4, b = - 4, c = - 3

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

u_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 (- 3) = 8

(- 4)^{2} - 4 \cdot 4 (- 3)

使用法则

- (- a) = a

= (- 4)^{2} + 4 \cdot 4 \cdot 3

使用指数法则:

(- a)^{n} = a^{n},

若

n

是偶数

(- 4)^{2} = 4^{2}

= 4^{2} + 4 \cdot 4 \cdot 3

数字相乘:

4 \cdot 4 \cdot 3 = 48

= 4^{2} + 48

4^{2} = 16

= 16 + 48

数字相加:

16 + 48 = 64

= 64

因式分解数字:

64 = 8^{2}

= 8^{2}

使用根式运算法则:

n a^{n} = a

8^{2} = 8

= 8

u_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 4}

将解分隔开

u_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 4}, u_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 4}

u = \frac{- ( - 4 ) + 8}{2 \cdot 4} : \frac{3}{2}

\frac{- ( - 4 ) + 8}{2 \cdot 4}

使用法则

- (- a) = a

= \frac{4 + 8}{2 \cdot 4}

数字相加:

4 + 8 = 12

= \frac{12}{2 \cdot 4}

数字相乘:

2 \cdot 4 = 8

= \frac{12}{8}

约分:

4

= \frac{3}{2}

u = \frac{- ( - 4 ) - 8}{2 \cdot 4} : - \frac{1}{2}

\frac{- ( - 4 ) - 8}{2 \cdot 4}

使用法则

- (- a) = a

= \frac{4 - 8}{2 \cdot 4}

数字相减:

4 - 8 = - 4

= \frac{- 4}{2 \cdot 4}

数字相乘:

2 \cdot 4 = 8

= \frac{- 4}{8}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4}{8}

约分:

4

= - \frac{1}{2}

二次方程组的解是:

u = \frac{3}{2}, u = - \frac{1}{2}

u = cos (β)

代回

cos (β) = \frac{3}{2}, cos (β) = - \frac{1}{2}

cos (β) = \frac{3}{2}, cos (β) = - \frac{1}{2}

cos (β) = \frac{3}{2} :

无解

cos (β) = \frac{3}{2}

- 1 \leq cos (x) \leq 1

无解

cos (β) = - \frac{1}{2} : β = \frac{2 π}{3} + 2 πn, β = \frac{4 π}{3} + 2 πn

cos (β) = - \frac{1}{2}

cos (β) = - \frac{1}{2}

的通解

cos (x)

周期表（周期为

2 πn

）：

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

β = \frac{2 π}{3} + 2 πn, β = \frac{4 π}{3} + 2 πn

β = \frac{2 π}{3} + 2 πn, β = \frac{4 π}{3} + 2 πn

合并所有解

β = \frac{2 π}{3} + 2 πn, β = \frac{4 π}{3} + 2 πn

作图

流行的例子

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