cos(θ)=-(sqrt(11))/6

Lösung

cos (θ) = - \frac{11}{6}

θ = 2.15648 \dots + 2 πn, θ = - 2.15648 \dots + 2 πn

Grad

θ = 123.55730 \dots^{\circ} + 36 0^{\circ} n, θ = - 123.55730 \dots^{\circ} + 36 0^{\circ} n

Schritte zur Lösung

cos (θ) = - \frac{11}{6}

Wende die Eigenschaften der Trigonometrie an

cos (θ) = - \frac{11}{6}

Allgemeine Lösung für

cos (θ) = - \frac{11}{6}

cos (x) = - a \Rightarrow x = arccos (- a) + 2 πn, x = - arccos (- a) + 2 πn

θ = arccos (- \frac{11}{6}) + 2 πn, θ = - arccos (- \frac{11}{6}) + 2 πn

θ = arccos (- \frac{11}{6}) + 2 πn, θ = - arccos (- \frac{11}{6}) + 2 πn

Zeige Lösungen in Dezimalform

θ = 2.15648 \dots + 2 πn, θ = - 2.15648 \dots + 2 πn

sin^{2} (x) - csc^{2} (x) = tan^{2} (x) - cot^{2} (x)

sin (x) = \frac{53}{54}

2 sin^{2} (x) + sin (x) - 3 = 0

(2 cos (x) - 1) sin (x) = 0

so l v e f or u, x = 4 sin (u)