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cos(2x+30)> 1/2

Solución

cos (2 x + 3 0^{\circ}) > \frac{1}{2}

Solución

\frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn < x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

Notación de intervalos

(\frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn, \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn)

Notación decimal

- 0.78539 \dots + πn < x < 0.26179 \dots + πn

Pasos de solución

cos (2 x + 3 0^{\circ}) > \frac{1}{2}

Para

cos (x) > a

, si

- 1 \leq a < 1

entonces

- arccos (a) + 2 πn < x < arccos (a) + 2 πn

- arccos (\frac{1}{2}) + 2 πn < (2 x + 3 0^{\circ}) < arccos (\frac{1}{2}) + 2 πn

a < u < b

entonces

a < u and u < b

- arccos (\frac{1}{2}) + 2 πn < 2 x + 3 0^{\circ} and 2 x + 3 0^{\circ} < arccos (\frac{1}{2}) + 2 πn

- arccos (\frac{1}{2}) + 2 πn < 2 x + 3 0^{\circ} : x > \frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn

- arccos (\frac{1}{2}) + 2 πn < 2 x + 3 0^{\circ}

Intercambiar lados

2 x + 3 0^{\circ} > - arccos (\frac{1}{2}) + 2 πn

Simplificar

- arccos (\frac{1}{2}) + 2 πn : - \frac{π}{3} + 2 πn

- arccos (\frac{1}{2}) + 2 πn

Utilizar la siguiente identidad trivial:

arccos (\frac{1}{2}) = \frac{π}{3}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{π}{3} + 2 πn

2 x + 3 0^{\circ} > - \frac{π}{3} + 2 πn

Mover

3 0^{\circ}

al lado derecho

2 x + 3 0^{\circ} > - \frac{π}{3} + 2 πn

Restar

3 0^{\circ}

de ambos lados

2 x + 3 0^{\circ} - 3 0^{\circ} > - \frac{π}{3} + 2 πn - 3 0^{\circ}

Simplificar

2 x > - \frac{π}{3} + 2 πn - 3 0^{\circ}

2 x > - \frac{π}{3} + 2 πn - 3 0^{\circ}

Dividir ambos lados entre

2

2 x > - \frac{π}{3} + 2 πn - 3 0^{\circ}

Dividir ambos lados entre

2

\frac{2 x}{2} > - \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Simplificar

\frac{2 x}{2} > - \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Simplificar

\frac{2 x}{2} : x

\frac{2 x}{2}

Dividir:

\frac{2}{2} = 1

= x

Simplificar

- \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2} : πn - \frac{π}{6} - 1 5^{\circ}

- \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Agrupar términos semejantes

= \frac{2 πn}{2} - \frac{\frac{π}{3}}{2} - \frac{3 0 ^{\circ}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Dividir:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{3}}{2} = \frac{π}{6}

\frac{\frac{π}{3}}{2}

Aplicar las propiedades de las fracciones:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 2}

Multiplicar los numeros:

3 \cdot 2 = 6

= \frac{π}{6}

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

Factorizar

3 0^{\circ} : 2^{\circ} \cdot 3^{\circ} \cdot 5^{\circ}

Factorizar

30 = 2 \cdot 3 \cdot 5

= (2 \cdot 3 \cdot 5)^{\circ}

Aplicar las leyes de los exponentes:

(ab)^{c} = a^{c} b^{c}

= 2^{\circ} \cdot 3^{\circ} \cdot 5^{\circ}

= \frac{2 ^{\circ} \cdot 3 ^{\circ} \cdot 5 ^{\circ}}{2}

Eliminar los terminos comunes:

2^{\circ}

= 3^{\circ} \cdot 5^{\circ}

Aplicar las leyes de los exponentes:

a^{m} b^{m} = (ab)^{m}

3^{\circ} \cdot 5^{\circ} = (3 \cdot 5)^{\circ}

= (3 \cdot 5)^{\circ}

Multiplicar los numeros:

3 \cdot 5 = 15

= 1 5^{\circ}

= πn - \frac{π}{6} - 1 5^{\circ}

x > πn - \frac{π}{6} - 1 5^{\circ}

x > πn - \frac{π}{6} - 1 5^{\circ}

Simplificar

- \frac{π}{6} - 1 5^{\circ} : \frac{- π - 6 \cdot 1 5 ^{\circ}}{6}

- \frac{π}{6} - 1 5^{\circ}

Convertir a fracción:

1 5^{\circ} = \frac{1 5 ^{\circ} \cdot 6}{6}

= - \frac{π}{6} - \frac{1 5 ^{\circ} \cdot 6}{6}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- π - 1 5 ^{\circ} \cdot 6}{6}

x > \frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn

x > \frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn

2 x + 3 0^{\circ} < arccos (\frac{1}{2}) + 2 πn : x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

2 x + 3 0^{\circ} < arccos (\frac{1}{2}) + 2 πn

Simplificar

arccos (\frac{1}{2}) + 2 πn : \frac{π}{3} + 2 πn

arccos (\frac{1}{2}) + 2 πn

Utilizar la siguiente identidad trivial:

arccos (\frac{1}{2}) = \frac{π}{3}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{3} + 2 πn

2 x + 3 0^{\circ} < \frac{π}{3} + 2 πn

Mover

3 0^{\circ}

al lado derecho

2 x + 3 0^{\circ} < \frac{π}{3} + 2 πn

Restar

3 0^{\circ}

de ambos lados

2 x + 3 0^{\circ} - 3 0^{\circ} < \frac{π}{3} + 2 πn - 3 0^{\circ}

Simplificar

2 x < \frac{π}{3} + 2 πn - 3 0^{\circ}

2 x < \frac{π}{3} + 2 πn - 3 0^{\circ}

Dividir ambos lados entre

2

2 x < \frac{π}{3} + 2 πn - 3 0^{\circ}

Dividir ambos lados entre

2

\frac{2 x}{2} < \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Simplificar

\frac{2 x}{2} < \frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Simplificar

\frac{2 x}{2} : x

\frac{2 x}{2}

Dividir:

\frac{2}{2} = 1

= x

Simplificar

\frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2} : πn + \frac{π}{6} - 1 5^{\circ}

\frac{\frac{π}{3}}{2} + \frac{2 πn}{2} - \frac{3 0 ^{\circ}}{2}

Agrupar términos semejantes

= \frac{2 πn}{2} + \frac{\frac{π}{3}}{2} - \frac{3 0 ^{\circ}}{2}

\frac{2 πn}{2} = πn

\frac{2 πn}{2}

Dividir:

\frac{2}{2} = 1

= πn

\frac{\frac{π}{3}}{2} = \frac{π}{6}

\frac{\frac{π}{3}}{2}

Aplicar las propiedades de las fracciones:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{π}{3 \cdot 2}

Multiplicar los numeros:

3 \cdot 2 = 6

= \frac{π}{6}

\frac{3 0 ^{\circ}}{2} = 1 5^{\circ}

\frac{3 0 ^{\circ}}{2}

Factorizar

3 0^{\circ} : 2^{\circ} \cdot 3^{\circ} \cdot 5^{\circ}

Factorizar

30 = 2 \cdot 3 \cdot 5

= (2 \cdot 3 \cdot 5)^{\circ}

Aplicar las leyes de los exponentes:

(ab)^{c} = a^{c} b^{c}

= 2^{\circ} \cdot 3^{\circ} \cdot 5^{\circ}

= \frac{2 ^{\circ} \cdot 3 ^{\circ} \cdot 5 ^{\circ}}{2}

Eliminar los terminos comunes:

2^{\circ}

= 3^{\circ} \cdot 5^{\circ}

Aplicar las leyes de los exponentes:

a^{m} b^{m} = (ab)^{m}

3^{\circ} \cdot 5^{\circ} = (3 \cdot 5)^{\circ}

= (3 \cdot 5)^{\circ}

Multiplicar los numeros:

3 \cdot 5 = 15

= 1 5^{\circ}

= πn + \frac{π}{6} - 1 5^{\circ}

x < πn + \frac{π}{6} - 1 5^{\circ}

x < πn + \frac{π}{6} - 1 5^{\circ}

Simplificar

\frac{π}{6} - 1 5^{\circ} : \frac{π - 6 \cdot 1 5 ^{\circ}}{6}

\frac{π}{6} - 1 5^{\circ}

Convertir a fracción:

1 5^{\circ} = \frac{1 5 ^{\circ} \cdot 6}{6}

= \frac{π}{6} - \frac{1 5 ^{\circ} \cdot 6}{6}

Ya que los denominadores son iguales, combinar las fracciones:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{π - 1 5 ^{\circ} \cdot 6}{6}

x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

Combinar los rangos

x > \frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn and x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

Mezclar intervalos sobrepuestos

\frac{- π - 6 \cdot 1 5 ^{\circ}}{6} + πn < x < \frac{π - 6 \cdot 1 5 ^{\circ}}{6} + πn

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