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Popular >

cos(x/2)>(sqrt(2))/2

Solución

cos (\frac{x}{2}) > \frac{2}{2}

Solución

- \frac{π}{2} + 4 πn < x < \frac{π}{2} + 4 πn

Notación de intervalos

(- \frac{π}{2} + 4 πn, \frac{π}{2} + 4 πn)

Notación decimal

- 1.57079 \dots + 4 πn < x < 1.57079 \dots + 4 πn

Pasos de solución

cos (\frac{x}{2}) > \frac{2}{2}

Para

cos (x) > a

, si

- 1 \leq a < 1

entonces

- arccos (a) + 2 πn < x < arccos (a) + 2 πn

- arccos (\frac{2}{2}) + 2 πn < \frac{x}{2} < arccos (\frac{2}{2}) + 2 πn

a < u < b

entonces

a < u and u < b

- arccos (\frac{2}{2}) + 2 πn < \frac{x}{2} and \frac{x}{2} < arccos (\frac{2}{2}) + 2 πn

- arccos (\frac{2}{2}) + 2 πn < \frac{x}{2} : x > - \frac{π}{2} + 4 πn

- arccos (\frac{2}{2}) + 2 πn < \frac{x}{2}

Intercambiar lados

\frac{x}{2} > - arccos (\frac{2}{2}) + 2 πn

Simplificar

- arccos (\frac{2}{2}) + 2 πn : - \frac{π}{4} + 2 πn

- arccos (\frac{2}{2}) + 2 πn

Utilizar la siguiente identidad trivial:

arccos (\frac{2}{2}) = \frac{π}{4}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{π}{4} + 2 πn

\frac{x}{2} > - \frac{π}{4} + 2 πn

Multiplicar ambos lados por

2

\frac{x}{2} > - \frac{π}{4} + 2 πn

Multiplicar ambos lados por

2

\frac{2 x}{2} > - 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplificar

\frac{2 x}{2} > - 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplificar

\frac{2 x}{2} : x

\frac{2 x}{2}

Dividir:

\frac{2}{2} = 1

= x

Simplificar

- 2 \cdot \frac{π}{4} + 2 \cdot 2 πn : - \frac{π}{2} + 4 πn

- 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

2 \cdot \frac{π}{4} = \frac{π}{2}

2 \cdot \frac{π}{4}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{4}

Eliminar los terminos comunes:

2

= \frac{π}{2}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiplicar los numeros:

2 \cdot 2 = 4

= 4 πn

= - \frac{π}{2} + 4 πn

x > - \frac{π}{2} + 4 πn

x > - \frac{π}{2} + 4 πn

x > - \frac{π}{2} + 4 πn

\frac{x}{2} < arccos (\frac{2}{2}) + 2 πn : x < \frac{π}{2} + 4 πn

\frac{x}{2} < arccos (\frac{2}{2}) + 2 πn

Simplificar

arccos (\frac{2}{2}) + 2 πn : \frac{π}{4} + 2 πn

arccos (\frac{2}{2}) + 2 πn

Utilizar la siguiente identidad trivial:

arccos (\frac{2}{2}) = \frac{π}{4}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{4} + 2 πn

\frac{x}{2} < \frac{π}{4} + 2 πn

Multiplicar ambos lados por

2

\frac{x}{2} < \frac{π}{4} + 2 πn

Multiplicar ambos lados por

2

\frac{2 x}{2} < 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplificar

\frac{2 x}{2} < 2 \cdot \frac{π}{4} + 2 \cdot 2 πn

Simplificar

\frac{2 x}{2} : x

\frac{2 x}{2}

Dividir:

\frac{2}{2} = 1

= x

Simplificar

2 \cdot \frac{π}{4} + 2 \cdot 2 πn : \frac{π}{2} + 4 πn

2 \cdot \frac{π}{4} + 2 \cdot 2 πn

2 \cdot \frac{π}{4} = \frac{π}{2}

2 \cdot \frac{π}{4}

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{π 2}{4}

Eliminar los terminos comunes:

2

= \frac{π}{2}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

Multiplicar los numeros:

2 \cdot 2 = 4

= 4 πn

= \frac{π}{2} + 4 πn

x < \frac{π}{2} + 4 πn

x < \frac{π}{2} + 4 πn

x < \frac{π}{2} + 4 πn

Combinar los rangos

x > - \frac{π}{2} + 4 πn and x < \frac{π}{2} + 4 πn

Mezclar intervalos sobrepuestos

- \frac{π}{2} + 4 πn < x < \frac{π}{2} + 4 πn

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24sin(θ)>0.06

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4cos(pi/2+x)+3<= 0

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