ko

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

인기 있는 삼각법 >

cos(x/2)+1/2 >0

해법

cos (\frac{x}{2}) + \frac{1}{2} > 0

해법

- \frac{4 π}{3} + 4 πn < x < \frac{4 π}{3} + 4 πn

+2

간격 표기법

(- \frac{4 π}{3} + 4 πn, \frac{4 π}{3} + 4 πn)

소수

- 4.18879 \dots + 4 πn < x < 4.18879 \dots + 4 πn

솔루션 단계

cos (\frac{x}{2}) + \frac{1}{2} > 0

\frac{1}{2}

를 오른쪽으로 이동

cos (\frac{x}{2}) + \frac{1}{2} > 0

빼다

\frac{1}{2}

양쪽에서

cos (\frac{x}{2}) + \frac{1}{2} - \frac{1}{2} > 0 - \frac{1}{2}

단순화

cos (\frac{x}{2}) > - \frac{1}{2}

cos (\frac{x}{2}) > - \frac{1}{2}

위해서

cos (x) > a

, 이면

- 1 \leq a < 1

그렇다면

- arccos (a) + 2 πn < x < arccos (a) + 2 πn

- arccos (- \frac{1}{2}) + 2 πn < \frac{x}{2} < arccos (- \frac{1}{2}) + 2 πn

만약에

a < u < b

그렇다면

a < u and u < b

- arccos (- \frac{1}{2}) + 2 πn < \frac{x}{2} and \frac{x}{2} < arccos (- \frac{1}{2}) + 2 πn

- arccos (- \frac{1}{2}) + 2 πn < \frac{x}{2} : x > - \frac{4 π}{3} + 4 πn

- arccos (- \frac{1}{2}) + 2 πn < \frac{x}{2}

측면 전환

\frac{x}{2} > - arccos (- \frac{1}{2}) + 2 πn

- arccos (- \frac{1}{2}) + 2 πn

간소화하다 :

- \frac{2 π}{3} + 2 πn

- arccos (- \frac{1}{2}) + 2 πn

다음과 같은 사소한 아이덴티티 사용:

arccos (- \frac{1}{2}) = \frac{2 π}{3}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{2 π}{3} + 2 πn

\frac{x}{2} > - \frac{2 π}{3} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} > - \frac{2 π}{3} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} > - 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} > - 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

- 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

간소화하다 :

- \frac{4 π}{3} + 4 πn

- 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{2 π}{3} = \frac{4 π}{3}

2 \cdot \frac{2 π}{3}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 π 2}{3}

숫자를 곱하시오:

2 \cdot 2 = 4

= \frac{4 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= - \frac{4 π}{3} + 4 πn

x > - \frac{4 π}{3} + 4 πn

x > - \frac{4 π}{3} + 4 πn

x > - \frac{4 π}{3} + 4 πn

\frac{x}{2} < arccos (- \frac{1}{2}) + 2 πn : x < \frac{4 π}{3} + 4 πn

\frac{x}{2} < arccos (- \frac{1}{2}) + 2 πn

arccos (- \frac{1}{2}) + 2 πn

간소화하다 :

\frac{2 π}{3} + 2 πn

arccos (- \frac{1}{2}) + 2 πn

다음과 같은 사소한 아이덴티티 사용:

arccos (- \frac{1}{2}) = \frac{2 π}{3}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{2 π}{3} + 2 πn

\frac{x}{2} < \frac{2 π}{3} + 2 πn

양쪽을 곱한 값

2

\frac{x}{2} < \frac{2 π}{3} + 2 πn

양쪽을 곱한 값

2

\frac{2 x}{2} < 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

단순화

\frac{2 x}{2} < 2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

\frac{2 x}{2}

간소화하다 :

x

\frac{2 x}{2}

숫자를 나눕니다:

\frac{2}{2} = 1

= x

2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

간소화하다 :

\frac{4 π}{3} + 4 πn

2 \cdot \frac{2 π}{3} + 2 \cdot 2 πn

2 \cdot \frac{2 π}{3} = \frac{4 π}{3}

2 \cdot \frac{2 π}{3}

다중 분수:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 π 2}{3}

숫자를 곱하시오:

2 \cdot 2 = 4

= \frac{4 π}{3}

2 \cdot 2 πn = 4 πn

2 \cdot 2 πn

숫자를 곱하시오:

2 \cdot 2 = 4

= 4 πn

= \frac{4 π}{3} + 4 πn

x < \frac{4 π}{3} + 4 πn

x < \frac{4 π}{3} + 4 πn

x < \frac{4 π}{3} + 4 πn

간격 결합

x > - \frac{4 π}{3} + 4 πn and x < \frac{4 π}{3} + 4 πn

중복 구간 병합

- \frac{4 π}{3} + 4 πn < x < \frac{4 π}{3} + 4 πn

인기 있는 예

cos^2(θ)>= 1/2

cos^{2} (θ) \geq \frac{1}{2}

sin(x)cos(x)<= 1

sin (x) cos (x) \leq 1

cos(θ)>0,cot(θ)<0

cos (θ) > 0, cot (θ) < 0

(cot(x))^2<1,0<= x<= 2pi

(cot (x))^{2} < 1, 0 \leq x \leq 2 π

5 > 4 + sin (n)