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Popular >

cos(x)>= 1/2 sqrt(3)

Solución

cos (x) \geq \frac{1}{2} 3

Solución

- \frac{π}{6} + 2 πn \leq x \leq \frac{π}{6} + 2 πn

+2

Notación de intervalos

[- \frac{π}{6} + 2 πn, \frac{π}{6} + 2 πn]

Notación decimal

- 0.52359 \dots + 2 πn \leq x \leq 0.52359 \dots + 2 πn

Pasos de solución

cos (x) \geq \frac{1}{2} 3

Simplificar

\frac{1}{2} 3 : \frac{3}{2}

\frac{1}{2} 3

Multiplicar fracciones:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 3}{2}

Multiplicar:

1 \cdot 3 = 3

= \frac{3}{2}

Para

cos (x) \geq a

, si

- 1 < a < 1

entonces

- arccos (a) + 2 πn \leq x \leq arccos (a) + 2 πn

- arccos (\frac{3}{2}) + 2 πn \leq x \leq arccos (\frac{3}{2}) + 2 πn

Simplificar

- arccos (\frac{3}{2}) : - \frac{π}{6}

- arccos (\frac{3}{2})

Utilizar la siguiente identidad trivial:

arccos (\frac{3}{2}) = \frac{π}{6}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= - \frac{π}{6}

Simplificar

arccos (\frac{3}{2}) : \frac{π}{6}

arccos (\frac{3}{2})

Utilizar la siguiente identidad trivial:

arccos (\frac{3}{2}) = \frac{π}{6}

x - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 arccos (x) π \frac{5 π}{6} \frac{3 π}{4} \frac{2 π}{3} \frac{π}{2} \frac{π}{3} \frac{π}{4} \frac{π}{6} 0 arccos (x) 18 0^{\circ} 15 0^{\circ} 13 5^{\circ} 12 0^{\circ} 9 0^{\circ} 6 0^{\circ} 4 5^{\circ} 3 0^{\circ} 0^{\circ}

= \frac{π}{6}

- \frac{π}{6} + 2 πn \leq x \leq \frac{π}{6} + 2 πn

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