해법
9.8⋅sin(α)−1.96⋅cos(α)=0.47
해법
α=−2.99124…+2πn,α=0.24444…+2πn
+1
도
α=−171.38555…∘+360∘n,α=14.00542…∘+360∘n솔루션 단계
9.8sin(α)−1.96cos(α)=0.47
더하다 1.96cos(α) 양쪽으로9.8sin(α)=0.47+1.96cos(α)
양쪽을 제곱(9.8sin(α))2=(0.47+1.96cos(α))2
빼다 (0.47+1.96cos(α))2 양쪽에서96.04sin2(α)−0.2209−1.8424cos(α)−3.8416cos2(α)=0
삼각성을 사용하여 다시 쓰기
−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04sin2(α)
피타고라스 정체성 사용: cos2(x)+sin2(x)=1sin2(x)=1−cos2(x)=−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04(1−cos2(α))
−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04(1−cos2(α))간소화하다 :−99.8816cos2(α)−1.8424cos(α)+95.8191
−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04(1−cos2(α))
96.04(1−cos2(α))확대한다:96.04−96.04cos2(α)
96.04(1−cos2(α))
분배 법칙 적용: a(b−c)=ab−aca=96.04,b=1,c=cos2(α)=96.04⋅1−96.04cos2(α)
=1⋅96.04−96.04cos2(α)
숫자를 곱하시오: 1⋅96.04=96.04=96.04−96.04cos2(α)
=−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04−96.04cos2(α)
−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04−96.04cos2(α)단순화하세요:−99.8816cos2(α)−1.8424cos(α)+95.8191
−0.2209−1.8424cos(α)−3.8416cos2(α)+96.04−96.04cos2(α)
집단적 용어=−1.8424cos(α)−3.8416cos2(α)−96.04cos2(α)−0.2209+96.04
유사 요소 추가: −3.8416cos2(α)−96.04cos2(α)=−99.8816cos2(α)=−1.8424cos(α)−99.8816cos2(α)−0.2209+96.04
숫자 더하기/ 빼기: −0.2209+96.04=95.8191=−99.8816cos2(α)−1.8424cos(α)+95.8191
=−99.8816cos2(α)−1.8424cos(α)+95.8191
=−99.8816cos2(α)−1.8424cos(α)+95.8191
95.8191−1.8424cos(α)−99.8816cos2(α)=0
대체로 해결
95.8191−1.8424cos(α)−99.8816cos2(α)=0
하게: cos(α)=u95.8191−1.8424u−99.8816u2=0
95.8191−1.8424u−99.8816u2=0:u=−199.76321.8424+38285.654512,u=199.763238285.654512−1.8424
95.8191−1.8424u−99.8816u2=0
표준 양식으로 작성 ax2+bx+c=0−99.8816u2−1.8424u+95.8191=0
쿼드 공식으로 해결
−99.8816u2−1.8424u+95.8191=0
4차 방정식 공식:
위해서 a=−99.8816,b=−1.8424,c=95.8191u1,2=2(−99.8816)−(−1.8424)±(−1.8424)2−4(−99.8816)⋅95.8191
u1,2=2(−99.8816)−(−1.8424)±(−1.8424)2−4(−99.8816)⋅95.8191
(−1.8424)2−4(−99.8816)⋅95.8191=38285.654512
(−1.8424)2−4(−99.8816)⋅95.8191
규칙 적용 −(−a)=a=(−1.8424)2+4⋅99.8816⋅95.8191
지수 규칙 적용: (−a)n=an,이면 n 균등하다(−1.8424)2=1.84242=1.84242+4⋅95.8191⋅99.8816
숫자를 곱하시오: 4⋅99.8816⋅95.8191=38282.26007…=1.84242+38282.26007…
1.84242=3.39443776=3.39443776+38282.26007…
숫자 추가: 3.39443776+38282.26007…=38285.654512=38285.654512
u1,2=2(−99.8816)−(−1.8424)±38285.654512
솔루션 분리u1=2(−99.8816)−(−1.8424)+38285.654512,u2=2(−99.8816)−(−1.8424)−38285.654512
u=2(−99.8816)−(−1.8424)+38285.654512:−199.76321.8424+38285.654512
2(−99.8816)−(−1.8424)+38285.654512
괄호 제거: (−a)=−a,−(−a)=a=−2⋅99.88161.8424+38285.654512
숫자를 곱하시오: 2⋅99.8816=199.7632=−199.76321.8424+38285.654512
분수 규칙 적용: −ba=−ba=−199.76321.8424+38285.654512
u=2(−99.8816)−(−1.8424)−38285.654512:199.763238285.654512−1.8424
2(−99.8816)−(−1.8424)−38285.654512
괄호 제거: (−a)=−a,−(−a)=a=−2⋅99.88161.8424−38285.654512
숫자를 곱하시오: 2⋅99.8816=199.7632=−199.76321.8424−38285.654512
분수 규칙 적용: −b−a=ba1.8424−38285.654512=−(38285.654512−1.8424)=199.763238285.654512−1.8424
2차 방정식의 해는 다음과 같다:u=−199.76321.8424+38285.654512,u=199.763238285.654512−1.8424
뒤로 대체 u=cos(α)cos(α)=−199.76321.8424+38285.654512,cos(α)=199.763238285.654512−1.8424
cos(α)=−199.76321.8424+38285.654512,cos(α)=199.763238285.654512−1.8424
cos(α)=−199.76321.8424+38285.654512:α=arccos(−199.76321.8424+38285.654512)+2πn,α=−arccos(−199.76321.8424+38285.654512)+2πn
cos(α)=−199.76321.8424+38285.654512
트리거 역속성 적용
cos(α)=−199.76321.8424+38285.654512
일반 솔루션 cos(α)=−199.76321.8424+38285.654512cos(x)=−a⇒x=arccos(−a)+2πn,x=−arccos(−a)+2πnα=arccos(−199.76321.8424+38285.654512)+2πn,α=−arccos(−199.76321.8424+38285.654512)+2πn
α=arccos(−199.76321.8424+38285.654512)+2πn,α=−arccos(−199.76321.8424+38285.654512)+2πn
cos(α)=199.763238285.654512−1.8424:α=arccos(199.763238285.654512−1.8424)+2πn,α=2π−arccos(199.763238285.654512−1.8424)+2πn
cos(α)=199.763238285.654512−1.8424
트리거 역속성 적용
cos(α)=199.763238285.654512−1.8424
일반 솔루션 cos(α)=199.763238285.654512−1.8424cos(x)=a⇒x=arccos(a)+2πn,x=2π−arccos(a)+2πnα=arccos(199.763238285.654512−1.8424)+2πn,α=2π−arccos(199.763238285.654512−1.8424)+2πn
α=arccos(199.763238285.654512−1.8424)+2πn,α=2π−arccos(199.763238285.654512−1.8424)+2πn
모든 솔루션 결합α=arccos(−199.76321.8424+38285.654512)+2πn,α=−arccos(−199.76321.8424+38285.654512)+2πn,α=arccos(199.763238285.654512−1.8424)+2πn,α=2π−arccos(199.763238285.654512−1.8424)+2πn
해법을 원래 방정식에 연결하여 검증
솔루션을 에 연결하여 확인합니다 9.8sin(α)−1.96cos(α)=0.47
방정식에 맞지 않는 것은 제거하십시오.
솔루션 확인 arccos(−199.76321.8424+38285.654512)+2πn:거짓
arccos(−199.76321.8424+38285.654512)+2πn
n=1끼우다 arccos(−199.76321.8424+38285.654512)+2π1
9.8sin(α)−1.96cos(α)=0.47 위한 {\ quad}끼우다{\ quad} α=arccos(−199.76321.8424+38285.654512)+2π19.8sin(arccos(−199.76321.8424+38285.654512)+2π1)−1.96cos(arccos(−199.76321.8424+38285.654512)+2π1)=0.47
다듬다3.40577…=0.47
⇒거짓
솔루션 확인 −arccos(−199.76321.8424+38285.654512)+2πn:참
−arccos(−199.76321.8424+38285.654512)+2πn
n=1끼우다 −arccos(−199.76321.8424+38285.654512)+2π1
9.8sin(α)−1.96cos(α)=0.47 위한 {\ quad}끼우다{\ quad} α=−arccos(−199.76321.8424+38285.654512)+2π19.8sin(−arccos(−199.76321.8424+38285.654512)+2π1)−1.96cos(−arccos(−199.76321.8424+38285.654512)+2π1)=0.47
다듬다0.47=0.47
⇒참
솔루션 확인 arccos(199.763238285.654512−1.8424)+2πn:참
arccos(199.763238285.654512−1.8424)+2πn
n=1끼우다 arccos(199.763238285.654512−1.8424)+2π1
9.8sin(α)−1.96cos(α)=0.47 위한 {\ quad}끼우다{\ quad} α=arccos(199.763238285.654512−1.8424)+2π19.8sin(arccos(199.763238285.654512−1.8424)+2π1)−1.96cos(arccos(199.763238285.654512−1.8424)+2π1)=0.47
다듬다0.47=0.47
⇒참
솔루션 확인 2π−arccos(199.763238285.654512−1.8424)+2πn:거짓
2π−arccos(199.763238285.654512−1.8424)+2πn
n=1끼우다 2π−arccos(199.763238285.654512−1.8424)+2π1
9.8sin(α)−1.96cos(α)=0.47 위한 {\ quad}끼우다{\ quad} α=2π−arccos(199.763238285.654512−1.8424)+2π19.8sin(2π−arccos(199.763238285.654512−1.8424)+2π1)−1.96cos(2π−arccos(199.763238285.654512−1.8424)+2π1)=0.47
다듬다−4.27346…=0.47
⇒거짓
α=−arccos(−199.76321.8424+38285.654512)+2πn,α=arccos(199.763238285.654512−1.8424)+2πn
해를 10진수 형식으로 표시α=−2.99124…+2πn,α=0.24444…+2πn