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Popular >

10sin(x)+10cos^2(x)=10,0<= x<2pi

Solución

10 sin (x) + 10 cos^{2} (x) = 10, 0 \leq x < 2 π

Solución

x = 0, x = π, x = \frac{π}{2}

+1

Pasos de solución

10 sin (x) + 10 cos^{2} (x) = 10, 0 \leq x < 2 π

Restar

10

de ambos lados

10 sin (x) + 10 cos^{2} (x) - 10 = 0

Re-escribir usando identidades trigonométricas

10 sin (x) - 10 sin^{2} (x) = 0

Usando el método de sustitución

sin (x) = 0, sin (x) = 1

sin (x) = 0, 0 \leq x < 2 π : x = 0, x = π

sin (x) = 1, 0 \leq x < 2 π : x = \frac{π}{2}

Combinar toda las soluciones

x = 0, x = π, x = \frac{π}{2}

Ejemplos populares

sin(x)-sqrt(3-3sin^2(x))=0

sin (x) - 3 - 3 sin^{2} (x) = 0

cos(2x)-cos(x)+1=0

cos (2 x) - cos (x) + 1 = 0

4tan^2(x)+21tan(x)-49=0

4 tan^{2} (x) + 21 tan (x) - 49 = 0

cot(x)=csc(x)+1

cot (x) = csc (x) + 1

(sin(8))/(30)=(sin(x))/(120)

\frac{sin ( 8 )}{30} = \frac{sin ( x )}{120}